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The density `("in g mL"^(-1))` of a 3.60 M sulphuric acid solution that is 29 % of acid by mass is : (Given molar mass `= 98 g mol^(-1)`)A. 1.45B. 1.64C. 1.88D. 1.22 |
Answer» Correct Answer - D By definition, `3.6 M(3.6xx98=352.8g)` of `H_(2)SO_(4)` are present in 1000 mL of the solution 29.0 g of acid are present in solution = 100 g 352.8 g of acid are present in solution `= ((100g)xx(352.8g))/((29g))` Density of solution `=("Mass of solution")/("Volume of solution")` `= ((1216g))/((1000mL))=1.22"g mL"^(-1)`. |
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