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The density (in g `mL^(-1)`) of a 3.60 M sulphuric acid solution that is 29% of acid by mass isA. `1.45`B. `1.64`C. `1.88`D. `1.22` |
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Answer» Correct Answer - D 3.6 M `H_(2)SO_(4)` means `3.6xx98=352.8g` of sulphuric acid are present in 1000 mL of the solution 29.0 g of acid are present in solution = 100 g 352.8 g of acid are present in solution `=((100g)xx(352.8g))/((29g))=1216g` Density of solution `= ("Mass of solution")/("Volume of solution")` `=(1216g)/(1000mL)=1.22gmL^(-1)` |
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