

InterviewSolution
Saved Bookmarks
1. |
The density of 2.0 M solution of a solute is `1.2 g mL^(-1)`. If the molecular mass of the solute is `100 g mol^(-1)`, then the molality of the solution isA. 2.0 mB. 1.2 mC. 1.0 mD. 0.6 m |
Answer» Correct Answer - A 2 M solution has 2 moles of solute dissolved in one litre (1000 mL) of the solution Mass of the solution `= V xx d = 1000 mL xx 1.2 "g mL"^(-1) = 1200 g` Mass of solvent `= (1200 - 200)g = 1000g = 1kg` Molality of solution (m) `= ("No. of moles of solute")/("Mass of solvent in Kg")` `("2 mol")/("1 kg")=2 "mol Kg"^(-1)=2`m. |
|