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| 1. |
The density of 2.03M aq. solution of acetic acid is 1.017g/ml. Calculate the molality of solution |
| Answer» We have , 2.03 moles of acetic acid in 1000 g of solvent. Mass of solution= 1000×1.017 =1017. (Mass= density ×vol.) Mass of solvent =1017-2.03×60 =895.2 Molality= 2.03×1000/60×895.2 = 0.037.. | |