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The density of 2 molal aqueous solution of NaOH is `1.10 "gm L"^(-1)`. Calculate the molarity of the solution. |
Answer» 2 molal NaOH solution represents 2 moles of solute of dissolved in 1000 g of water Mass of NaOH in 2 molal solution `= (2xx 40 g)=80g` Mass of solution = Mass of solute + Mass of solvent `=(80 +1000)=1080g` Volume of solution `= ("Mass)/("Density") = ((1080 g))/((1.1 "gm L"^(-1)))=981.8mL` Molarity of solution `(M)=("Moles of solute")/("Volume of solution in litres")` `=((2mol))/((981.8//1000L))=2.04"mol L"^(-1)=2.04M`. |
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