1.

The density of 2 molal aqueous solution of NaOH is `1.10 "gm L"^(-1)`. Calculate the molarity of the solution.

Answer» 2 molal NaOH solution represents 2 moles of solute of dissolved in 1000 g of water
Mass of NaOH in 2 molal solution `= (2xx 40 g)=80g`
Mass of solution = Mass of solute + Mass of solvent
`=(80 +1000)=1080g`
Volume of solution `= ("Mass)/("Density") = ((1080 g))/((1.1 "gm L"^(-1)))=981.8mL`
Molarity of solution `(M)=("Moles of solute")/("Volume of solution in litres")`
`=((2mol))/((981.8//1000L))=2.04"mol L"^(-1)=2.04M`.


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