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The density of `3 M` sodium of thiosulphate solution `(Na_(2)S_(2)O_(3))` is `1.25 g mL^(-1)`. Calculate a. The precentage by weight of sodium thiosulphate. b. The mole fraction of sodium thiosulphate. c. The molalities of `Na^(o+)` and `S_(2)O_(3)^(2-)` ions.A. `12.64%`B. `37.92%`C. `0.87%`D. `63.21%` |
Answer» Correct Answer - B Mass of 1000 mL of `Na_(2)S_(2)O_(3)` solution `=1.25xx1000=1250 g` Molarity `=("mass")/("molecular mass " xx " volume (mL)")xx100` `rArr 3=("mass " xx 1000)/(158xx1000)` `therefore` Mass of `Na_(2)S_(2)O_(3)` is 1000 mL of 3M solution `=3xx158=474 g` Percentage by weight of `Na_(2)S_(2)O_(3)` in solution `=(474)/(1250)xx100 =37.92 %` |
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