

InterviewSolution
Saved Bookmarks
1. |
The density of 3 molal solution of NaOH is 1.110g `mL^(-1)`. Calculate the molarity of the solution. |
Answer» 3 molal NaOH solution represents 3 moles of solute dissolved in 1000 g of water Mass of the solution = (Mass of the solute)+(Mass of the solvent) `=(3 mol xx 4 g mol^(-1))+(1000g)` `=120g + 1000g = 1120 g` Volume of the solution `= ("Mass")/("Density")=(1120 g)/((1.110 "g mL"^(-1)))=1009 mL` Molarity of the solution `(M)=("Moles of the solution")/("Volume of the solution in litres")=((3mol))/((1009//1000L))=2.97"mol L"^(-1)=2.97M` |
|