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The density of 5% aqueous `MgCl_(2)` solution is `1.043 g mL^(-1)`. What is the molarity and molaltiy of the solution? What is the molality of `Cl^(ɵ)` ions? `(Mg = 24 "amu")`

Answer» `Mw of MgCl_(2) = 24 + 35.5 xx 2 = 95 g`
`M = (% "by weight" xx 10 xx d)/(Mw_(2)) = (5 xx 10 xx 1.043)/(95) = 0.548`.
Weight of solvent `(W_(1)) = 100 - 5 = 95 g`
`m = (W_(2) xx 1000)/(Mw_(2) xx W_(1)) = (5 xx 1000)/(95 xx 95) = 0.554`
`{:(MgCl_(2)rarr, Mg^(2+), +, 2Cl^(ɵ)),(1m, 1m, 2m),(0.554m, 0.554 m, 2 xx 0.554):}`


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