1.

The density of a gas at `27^(@)C` and `1 atm` is `d`. Pressure remaining constant, at which of the following temperture will its density become `0.75 d`?A. `20^(@)C`B. `30^(@)C`C. `400 K`D. `300 K`

Answer» `(d)_(1)=d`
`(d)_(2)=0.75 d`
`P_(1)= 1 atm`, `T_(1)=27^(@)C=300 K`
`P_(2)=1 atm`, `T_(2)=?`
`((d_(1))/(d_(2)))=(P_(1)xxT_(2))/(T_(1)xxP_(2))` or `(T_(2))/(T_(1))`
`:. T_(2)=(d_(1))/(d_(2))xxT_(1)=(d)/(0.75d)xx300=400K`


Discussion

No Comment Found

Related InterviewSolutions