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The density of a non-uniform rod of length 1 m is given by rho(x)=a(1+bx^(2)) where, a and b are constants and 0lexle1. The centre of mass of the rod will be at ……….. |
Answer» <html><body><p>`(3(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>+b))/(4(3+b))`<br/>`(4(2+b))/(3(3+b))` <br/>`(3(3+b))/(4(2+b))` <br/>`(4(3+b))/(3(2+b))` </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/density-17451" style="font-weight:bold;" target="_blank" title="Click to know more about DENSITY">DENSITY</a> = `rho(x)=a(1+bx^(2))` <br/> if `b=0`, then `rho(x)=a` = constant <br/> Hence, centre of mass will be at <a href="https://interviewquestions.tuteehub.com/tag/middle-1096062" style="font-weight:bold;" target="_blank" title="Click to know more about MIDDLE">MIDDLE</a> of the rod, `x=0.5m`. Only (A) gives 0.5.</body></html> | |