The density of a non-uniform rod of length 1 m is given by rho(x)=a(1+bx^(2)) where, a and b are constants and 0lexle1. The centre of mass of the rod will be at ………..

The density of a non-uniform rod of length 1 m is given by rho(x)=a(1+

1.	The density of a non-uniform rod of length 1 m is given by rho(x)=a(1+bx^(2)) where, a and b are constants and 0lexle1. The centre of mass of the rod will be at ………..
Answer» `(3(2+b))/(4(3+b))` `(4(2+b))/(3(3+b))` `(3(3+b))/(4(2+b))` `(4(3+b))/(3(2+b))` SOLUTION :DENSITY = `rho(x)=a(1+bx^(2))` if `b=0`, then `rho(x)=a` = constant Hence, centre of mass will be at MIDDLE of the rod, `x=0.5m`. Only (A) gives 0.5.