InterviewSolution
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InterviewSolution
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The density of a non-uniform rod of length `1m` is given by `rho (x) = a (1 + bx^(2))` where a and b are constants and `0 le x le 1`. The centre of mass of the rod will be atA. `(3 (2+ b))/(4(3+b))`B. `(4 (2+ b))/(3(3+b))`C. `(3 (3+ b))/(4(2+b))`D. `(4 (3+ b))/(3(2+b))` |
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Answer» Correct Answer - A Here, `rho (x) = a (1 + bx^(2))` When `b rarr0, rho(x) = a = consatnt` i.e., density of rod of length 1 m is constant. In that event, centre of mass of rod would lie at `0.5 m` (i.e. at centre of rod). When we try `b rarr 0` in all four given options, we find choice (a) alone gives `x = (3(2 + b))/(4(3 + b)) = (6)/(12) = 0.5`. Therefore, choice (a) is correct. |
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