InterviewSolution
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InterviewSolution
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The density of a solution prepared by dissolving 120 g of urea (mol. Mass=60 u) in 1000 g of water is 1.15 g/mL. The molarity if this solution isA. (a)0.50 MB. (b)1.78 MC. (c )1.02 MD. (d)2.05 M |
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Answer» Correct Answer - D Total mass of `solution=1000 g water+120 g urea=1120 g` Density of solution`=1.15 g//mL` Thus, volume of solution=mass/density`=(1120g)/(1.15 g//mL)` `=973.91 mL=0.974 L` Moles of solute`=120/60=2 mol` `"Molarity"=("moles of solute")/("volume (L) of solution")` `=(2 "mol")/(0.974 L)=2.05 "mol" L^(-1)` |
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