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The density of a wire used in the experiment is 6.9 xx 10^(3) kg//m^(3). If a stress of 2.5 xx 10^(8) N//m^(2) is given to the wire, determine the speed of transverse wave in the wire. |
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Answer» Solution :Given, `RHO = 6.9 xx 10^(3) kg//m^(3)` Stress `= 2.5 xx 10^(8) N//m^(2)` If A is the area of cross SECTION of the WIRE, then tension in the wire T = Stress `xx` area `= (2.5 xx 10^(8) xx A)N` Mass per unit LENGTH is `m = A xx 1 xx rho = A xx 6.9 xx 10^(3) kg//m^(3)` `therefore` Speed of transverse wave. `upsilon = sqrt((T)/(m)) = sqrt((2.5 xx 10^(8) xx A)/(A xx 6.9 xx 10^(3)))` = 190.3 m/s |
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