1.

The density of earth increased 4 times and its radius becomes half then our weight will ....

Answer»

be four times its present VALUE
be doubled
remains same
be halved

Solution :`implies ` weight `W = mg = m((GM_e)/(R_e^2))`
`= ((G)/(R_e^2) xx4/3piR_e^3rho)`
`W = m (4/3 PI R_e) rho ""...(1)`
New weight if the density of EARTH increased four TIME and radius becomes half is
`W. = m (4/3 piR_e/2G) 4rho`
`= 2 [m(4/3 piR_e/2G) 4rho`
`= 2 [ m(4/3 pi GR_e) rho] "" ...(2)`
`:. W. = 2W`


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