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The density of ice is 901 kg m^(-3). What percentage of ice lies below water ? The density of sea water is 1011 kg m^(-3). What fraction of an iceberg can be seen by us if the ice berg has the same density as that of ice ? |
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Answer» Solution :(i) Apply the LAW of floatation. Weight of the FLOATING body = weight of the displaced liquid. This implies, V.D. =vd The PERCENTAGE of the ice lying celow the water is `=(v)/(V)xx100` Apply the same concept for the iceberg floating in sea water. The percentage of the iceberg lying above the sea water is `=(100-(v)/(V)xx100)` (II) 0.11 |
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