1.

The density of one hydrocarbon at `N.T.P` is `1.964g//`lite. Identify the hydrocarbon.

Answer» Molecular weight of Hydrocarbon
`=` density of `1` lit. `xx22.4=1.964xx22.4=44`
So molecular weight of hydrocarbon `=44`
So the hydrocarbon is `C_(3)H_(8)` (Propane).


Discussion

No Comment Found

Related InterviewSolutions