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The density of one hydrocarbon at `N.T.P` is `1.964g//`lite. Identify the hydrocarbon. |
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Answer» Molecular weight of Hydrocarbon `=` density of `1` lit. `xx22.4=1.964xx22.4=44` So molecular weight of hydrocarbon `=44` So the hydrocarbon is `C_(3)H_(8)` (Propane). |
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