Saved Bookmarks
| 1. |
The density of the atmosphere at sea level is 1.29 kg m-3. Assume that it does not change with altitude. Then how high would the atmosphere extend? |
|
Answer» Here, 1.01 × 105 = ρgh h = \(\frac{1.01×10^5}{ρg}\) = \(\frac{1.01×10^5}{1.29×9.8}\) = 7989 m. |
|