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The derivative of `sin^2x`with respect to `cos^2x`is equal to....A. `tan^2x`B. `tanx`C. `-tanx`D. None of these |
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Answer» Correct Answer - D Let `u=sin^2xxand v=cos^2x` On differenting w.r.t.x, respectively , we get `(du)/(dx)=2sinx cos x` and `(dv)/(dx)=-2sinxcosx` `therefore (du)/(dv)=(du//dx)/(dv//dx)=(2sinxcosx)/(-2sinxcosx)=-1` |
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