The diagonal of a square is 4√2 cm. The diagonal of another square

1.	The diagonal of a square is 4√2 cm. The diagonal of another square whose area is double that of the first square is:1. 8√22. √323. 8 cm4. 16 cm
Answer» Correct Answer - Option 3 : 8 cm Given: The length of the diagonal of the square is 4√2 cm Concept Used: If the length of one side of a square is 'a' unit then the length of diagonal of the square is a√2 unit. And the arear of the square is a² square unit. Calculation: Let, the length of one side of the square is 'a' unit ⇒ Length of the diagonal of the square is a√2 unit Accordingly, a√2 = 4√2 ⇒ a = 4 Area of the square is 4² = 16 cm² Accordingly, the area of the 2nd square is 2 × 16 = 32 cm² Let, the length of the side of the 2nd square is 'b' Accordingly, b² = 32 ⇒ b = √32 ⇒ b = 4√2 Length of the diagonal of the 2nd square is (4√2) × √2 ⇒ 8 cm ∴ The diagonal of another square whose area is double that of the first square is 8 cm.

The diagonal of a square is 4√2 cm. The diagonal of another square whose area is double that of the first square is:1. 8√22. √323. 8 cm4. 16 cm

Answer» Correct Answer - Option 3 : 8 cm

Given:

The length of the diagonal of the square is 4√2 cm

Concept Used:

If the length of one side of a square is 'a' unit then the length of diagonal of the square is a√2 unit.

And the arear of the square is a² square unit.

Calculation:

Let, the length of one side of the square is 'a' unit

⇒ Length of the diagonal of the square is a√2 unit

Accordingly,

a√2 = 4√2

⇒ a = 4

Area of the square is 4² = 16 cm²

Accordingly, the area of the 2nd square is 2 × 16 = 32 cm²

Let, the length of the side of the 2nd square is 'b'

Accordingly,

b² = 32

⇒ b = √32

⇒ b = 4√2

Length of the diagonal of the 2nd square is (4√2) × √2

⇒ 8 cm

∴ The diagonal of another square whose area is double that of the first square is 8 cm.

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