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The diagram given below shows a solenoid carrying time varying current `l= l_(0)t`. On the axis of the solenoid, a ring has been placed. The mutual inductance of the ring and the solenoid is M and the self inductance of the ring is L. If the resistance of the ring is R then maximum current which can flow through the ring is A. `((2M+L)I_(0))/(R)`B. `(MI_(0))/(R)`C. `((2M-L)I_(0))/(R)`D. `((M+L)I_(0))/(R)` |
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Answer» Correct Answer - B `phi=MI=MI_(0)t` Hence, induced emf `e=(d phi)/(dt)=MI_(0)` Current through ring `=e/R=(MI_(0))/(R)`. |
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