

InterviewSolution
Saved Bookmarks
1. |
The diagram in fig.1.33 shows two forces F1 = 5 N and F2 = 3N acting at points A and B of a rod pivoted at a point O, such that OA = 2m and OB = 4m.Calculate:(i) Moment of force F1 about O.(ii) Moment of force F2 about O.(iii) Total moment of the two forces about O. |
Answer» Given AO = 2m and OB = 4m (i) Moment of force F1(= 5N) at A about the point O = F1 × OA = 5 × 2 = 10Nm (anticlockwise) (ii) Moment of force F2 (= 3N) at B about the point O = F2 × OB = 3 × 4 =12 Nm(clockwise) (iii) Total moment of forces about the mid-point O = = 12 – 10 = 2 Nm (clockwise) |
|