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The diagram show a small bead of mass `m` carrying charge `q`. The bead can freely move on the smooth fixed ring placed on a smooth borizontal plane . In the same pane a charge ` +Q` has also been fixed as shown. The potential at the point ` P` due to ` +Q` is `V` . The velocity which the bead should projected from the point `P` so that it can complete a circle should be greater than . A. ` sqrt ( (6qV)/(m))`B. `sqrt ((qV)/(m))`C. ` sqrt( (3qV)/(m))`D. none |
Answer» Correct Answer - A From energy conservation ` QV + 1/2 mu^2 =Q. 4 V + 0 rArr 1/2 mu^2 = 3 QV` ` rArr u = sqrt ( 6 QV)/m` . |
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