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The diagram shows a concavo- convex lens. What is the condition on the refractive indices so that the lens is diverging? The refractive index of the lens is mu_2 |
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Answer» Solution :`mu_3/v_f+mu_1/u_0=(mu_2-mu_1)/(-2R)+(mu_3-mu_2)/(-R)` For DIVERGENCE `V_f` is NEGATIVE so, `(mu_1-mu_2)/(2R) lt (mu_3-mu_2)/ R` `IMPLIES mu_1-mu_2lt 2mu_3 -2mu_2 implies mu_1+mu_2 lt 2mu_3` |
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