The diameter of a brass rod is 4 mm and Young's modulus of brass is 9 xx 10 ^(9) Nm ^(-2),What will be the force required to stretch by 0.1% of its length ?

The diameter of a brass rod is 4 mm and Young's modulus of brass is 9

1.	The diameter of a brass rod is 4 mm and Young's modulus of brass is 9 xx 10 ^(9) Nm ^(-2),What will be the force required to stretch by 0.1% of its length ?
Answer» <html><body><p>`36pi N`<br/>`36 N`<br/>`36 pi xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a> ^(5) N`<br/>`144 pi xx 10 ^(3)N`</p>Solution :Longitudinal strain `(Delta <a href="https://interviewquestions.tuteehub.com/tag/l-535906" style="font-weight:bold;" target="_blank" title="Click to know more about L">L</a> )/(l) = (0.1)/(100) =1 xx 10 ^(-3)` <br/> Now `Y= (F)/(A) xx (l)/(Delta l )` <br/> `=F = YA xx (Deltal )/(l)` <br/> `= 9 xx 10 ^(9) xx pi <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> ^(2) xx 1 xx 10 ^(-3)` <br/> `= 0 xx 10 ^(9) xx pi xx(2 xx 10 ^(-3)) ^(2) xx 1 xx 10 ^(-3)` <br/> `= 36 pi xx 10 ^(0)` <br/> `= 36 pi N`</body></html>