InterviewSolution
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InterviewSolution
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The diameter of a gas molecule is `2.4 xx 10^(-10) m`. Calculate the mean free path at NTP. Given Boltzmann constant `k = 1.38 xx 10^(-23) J molecule^(-1) K^(-1)`. |
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Answer» Correct Answer - `1.46 xx 10^(-7)m`. Here, `d=2.4 xx 10^(-10)m, lambda = ?` `k =1.38 xx 10^(-23)J "molecule"^(-1) K^(-1)` At, NTP. `T = 273 K, P = 1.01 xx 10^(5) Nm^(-2)` `lambda = (kT)/(sqrt(2) pi d^(2)P)` `=(1.38 xx 10^(-23) xx 273)/(1.414 xx 3.14 (2.4 xx 10^(-10))xx 1.01 xx 10^(5))` `lambda = (1.38 xx 273 xx 10^(-1)xx10^(-7))/(1.414 xx 3.14 xx 2.4 xx 1.01)` `= 1.46 xx 10^(-7)m`. |
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