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The diameter of a roller 120cm long is 84cm. If its takes 500 complete revolutions to level a playground determine the cost of leveling at the rate of Rs. 25per square metre. (Use π = 22/7 ) |
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Answer» 2r = 84cm ∴ r = 84/2cm = 42cm h = 120cm Area of the playground leveled in one complete revolution = 2πrh = 2 × 22/7 × 42 × 120 × 31680cm2 ∴ Area of the playground = 31680 × 500cm2 = (31680 x 500)/(100 x 100)m2 = 1584m2 ∴ Cost of leveling @ Rs 25 per square metre = Rs 1584 × 25 = 39600. |
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