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The diameter of a soap bubble is 8mm and the surface tension of soap solution is 4xx10^(-2)Nm^(-1). Find the excess pressure inside the bubble. |
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Answer» Solution :Diameter of the bubble = `8mm=8xx10^(-3)m` RADIUS of the bubble `(r )=4XX10^(-3)m` Surface tension `(S)=4xx10^(-2)Nm^(-1)` Excess pressure inside the bubble `=(4S)/(r )` `=(4xx4xx10^(-2))/(4xx10^(-3))=40Nm^(-2)` `therefore` Excess pressure inside the bubble = `40Nm^(-2)` |
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