The diameter of cylinders are d_(1)=(2.02 pm 0.01)cm " and "d_(2)=(3.21 pm 0.03)cm respectively. Find the difference between their dimensions along with the error limits.

The diameter of cylinders are d_(1)=(2.02 pm 0.01)cm " and "d_(2)=(3.2

1.	The diameter of cylinders are d_(1)=(2.02 pm 0.01)cm " and "d_(2)=(3.21 pm 0.03)cm respectively. Find the difference between their dimensions along with the error limits.
Answer» Solution :`d_(1)=(2.02 pm 0.01)cm, d_(2)=(3.21 pm 0.03)cm` Difference `d= d_(2)-d_(1)= 3.21-2.02= 1.19cm` Maximum error in difference, `TRIANGLED= pm(triangled_(2)+triangled_(1))= pm (0.03+0.01)` Difference in DIAMETER `=(1.19 pm 0.04) cm`.