1.

The diameter of roller 1.5 m long is 84 cm. If it takes 100 revolutions to level a playground, find the cost of levelling this ground at the rate of 50 paise per square meter.

Answer»

Given,

Diameter of roller = 84 cm

So radius of roller =\(\cfrac{84}2\) = 42 cm = .42 m

Length of roller = 1.5 m

Area covered by roller in one revolution = 2πrh = 2 \(\times\cfrac{22}7\times \)4.2 \(\times\) 1.5 =  3.96 m2

Area covered by it in 100 revolution = 100 × 3.96 = 396 m2

Cost of levelling 1m2 area = Rs. .50

∴cost of levelling 396m2 = .50 × 396 = Rs. 198



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