1.

The diameter of the steel ball is measured using a vernier caliper which has divisions of 0.1 cm on its main scale nad 10 division of its vernier scale match 9 division on the main scale. Three such measurements for a ball are as follows. If the zero error is 0.03cm, then mean corrected diameter is ............. cm.

Answer»

0.56
0.53
0.59
0.52

Solution :LEAST COUNT = 0.01 CM
`ZE=-0.03cm`

`"Mean "=(0.61+0.57+0.59)/(3)`
`=1.77`
`therefore"Mean CORRECTED diameter"=0.59cm`


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