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The diameyer of zinc atom is `2.6 A`. Calculate (a) radius of zinc atom in pm and (b) number of atoms present in a length of `1.6 cm` if the zinc atoms are arranged side by side lengthwise. |
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Answer» a. Radius `=(2.6 Å)/2=1.3xx10^(-10)m=130xx10^(-12)m` `=130 p m` b. Given length `=1.6 cm=1.6xx10^(-2)m` Diameter of one atom `=2.6Å=2.6xx10^(-10)m` `:.` Number of atoms present along the length `=(1.6xx10^(-2))/(2.6xx10^(-10))=6.154xx10^(7)` |
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