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The differeence in the effective capacity of two similar capacitor when joined in series and then in paralllel is 6 `mu` F the capacity of each capacitor isA. `2muF`B. `4muF`C. `8muF`D. `16muF` |
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Answer» Correct Answer - B When two similar capacitor are joined in series, then effective capacity is `(1)/(C_(s))=(1)/(C)+(1)/(C)=(2)/(C)` `therefore" "C_(s)=(C)/(2)` When joined in parallel, `C_(p)=C+C=2C` Since, `" "C_(p)-C_(s)=6muF` `therefore" "2C-(C)/(2)=6` `rArr" "4C-C=12` `"or "C=4muF` |
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