

InterviewSolution
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The difference between squares of two numbers is 120. The square of smaller number is twice the greater number. Find the numbers. |
Answer» Let the numbers be x and y (x > y). According to the given condition, x2 – y2 = 120 …(i) y2 = 2x …(ii) Substituting y2 = 2x in equation (i), we get x2 – 2x = 120 ∴ x2 – 2x – 120 = 0 ∴ x2 – 12x + 10x – 120 = 0 ∴ x(x – 12) + 10(x – 12) = 0 ∴ (x – 12)(x + 10) = 0 By using the property, if the product of two numbers is zero, then at least one of them is zero, we get ∴ x – 12 = 0 or x + 10 = 0 ∴ x = 12 or x = -10 But x ≠ -10 as, y2 = 2x = 2(-10) = -20 …[Since, the square of number cannot be negative] ∴ x = 12 Smaller number = y2 =2x ∴ y2 = 2 × 12 ∴ y2 = 24 ∴ y = ± √24 …[Taking square root of both sides] ∴ The smaller number is √24 and greater number is 12 or the smaller number is – √24 and greater number is 12. |
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