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The difference between the longest wavelength line of the Balmer series and shortest wavelength lion of the Lyman series for a hydrogenic atom (Atomic number Z) equal to `Delta lambda`. The value of the Rydberg constant for the given atom isA. `(5)/(31)(1)/(Delta lambda.Z^(2))`B. `(5)/(36)(z^(2))/(Delta lambda)`C. `(31)/(5)(1)/(Delta lambda. Z^(2))`D. none |
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Answer» `Deltalambda =lambda_(1)-lambda_(2)=(1)/(R[(1)/((2)^(2))-(1)/((3)^(2))]z^(2))-(1)/(R[a-0]z^(2))` On solving, `R=(31)/(5)(1)/(Delta lambda.Z^(2))` |
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