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The difference between the radii of the largest and smallest circles which have their centres on the circumference of the circle `x^2 + y^2 + 2x + 4y -4 = 0` and passes through point (a,b) lying outside the circle is : |
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Answer» `x^2+y^2+2x+4y-4=0` `(x+1)^2+(y+2)^2-1-4-4=0` `(x+1)^2+(y+2)^2=3^2` AB is a diameter `r_m=AB+r_s` `r_m-r_s=AB=2*3=6`. |
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