The difference between the two acute angles of a right triangle is (π

1.	The difference between the two acute angles of a right triangle is (π/5)c. Find these angles in radians and degrees.
Answer» Angle in degree = π/5 x 180/π = 36° Let x and y are two acute angles of a right triangle. So, x – y= 36° ……(1) Also we know, x + y = 90° ……(2) Solving (1) and (2), we get 2x= 126° or x = 63° Form (2), 63° + y = 90° or y = 27° Therefore, two acute angles are 63° and 27°. Represent angle into radian: We know, Angle in radians = Angle in degrees x π/180° Angle in radians = 63°x π/180° = 7π/20 And Angle in radians = 27°x π/180° = 3π/20

The difference between the two acute angles of a right triangle is (π/5)c. Find these angles in radians and degrees.

Answer»

Angle in degree = π/5 x 180/π = 36°

Let x and y are two acute angles of a right triangle.

So, x – y= 36° ……(1)

Also we know,

x + y = 90° ……(2)

Solving (1) and (2), we get

2x= 126°

or x = 63°

Form (2), 63° + y = 90°

or y = 27°

Therefore, two acute angles are 63° and 27°.

Represent angle into radian:

We know, Angle in radians = Angle in degrees x π/180°

Angle in radians = 63°x π/180°

= 7π/20

And Angle in radians = 27°x π/180°

= 3π/20