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The differential equation `(dy)/(dx)=(7x-3y-7)/(-3x+7y+3)` reduces to homogeneous form by making the substitutionA. `x=X+1, y=Y+0`B. `x=X+1,y=Y+1`C. `x=X-1, y=Y+1`D. `x=X+0, y=Y+1`

Answer» Correct Answer - A
Let `x=X+h, y=Y+k`. Then, the given equation becomes
`(dY)/(dX)=((7X-3Y)+(7h-3k-7))/((-3X+7Y)+(03h+7k+3))`
This will reduces to a homogeneous differential equation, if
`7h-3k-7=0 and -3h+7k+3=0 rArr h=1, k=0`
Hence, `x=X+1, y=Y+0` reduces the given equation to homogeneous form.


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