The differential equation of family of curves y2=4a(x+a) is a) y2=4dyd – InterviewSolution

1.	The differential equation of family of curves y2=4a(x+a) is a) y2=4dydx(x+dydx) b) 2ydydx=4a c) yd2ydx2+(dydx)2=0 d) 2xdydx+y(dydx)2−y=0
Answer» The differential equation of family of curves $y^{2} = 4 a (x + a)$ is a) $y^{2} = 4 \frac{d y}{d x} (x + \frac{d y}{d x})$ b) $2 y \frac{d y}{d x} = 4 a$ c) $y \frac{d^{2} y}{d x^{2}} + {(\frac{d y}{d x})}^{2} = 0$ d) $2 x \frac{d y}{d x} + y {(\frac{d y}{d x})}^{2} - y = 0$

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