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The diffraction pattern of a single slit of width 0. 5 cm is formed by a lens of focal length 40 cm. Calculate the distance between the first dark and the next bright fringe from the axis. The wavelength of light used is 4890 Å. |
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Answer» Data : a = 0.5 cm = 0.5 × 10-2 m, D ≃ f = 40 cm = 0.4 m, λ = 4890 Å = 4.890 × 10-7 m The distance between the first dark fringe and the next bright fringe = \(\cfrac{λD}{2a}\) = \(\cfrac{4.890\times10^{-7}\times0.4}{2\times0.5\times10^{-2}}\) = 1.956 x 10-5 m |
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