1.

The diffraction pattern of a single slit of width 0. 5 cm is formed by a lens of focal length 40 cm. Calculate the distance between the first dark and the next bright fringe from the axis. The wavelength of light used is 4890 Å.

Answer»

Data : a = 0.5 cm = 0.5 × 10-2 m, 

D ≃ f = 40 cm = 0.4 m, λ = 4890 Å = 4.890 × 10-7 m

The distance between the first dark fringe and the next bright fringe = \(\cfrac{λD}{2a}\)

\(\cfrac{4.890\times10^{-7}\times0.4}{2\times0.5\times10^{-2}}\) = 1.956 x 10-5 m



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