The digit in the tens place of a two digit number is 3 more than the d

1.	The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is(a) 11b + 30 (b) 10b + 30 (c) 11b + 3 (d) 10b + 3
Answer» (a) 11b + 30 From the question it is given that, Let the digit at units place be b. The digit in the tens place of a two digit number is 3 more than the digit in the units place = 3 + b So, the number = 10 (3 + b) + b = 30 + 10b + b = 30 + 11b

The digit in the tens place of a two digit number is 3 more than the digit in the units place. Let the digit at units place be b. Then the number is(a) 11b + 30 (b) 10b + 30 (c) 11b + 3 (d) 10b + 3

Answer»

(a) 11b + 30

From the question it is given that,

Let the digit at units place be b.

The digit in the tens place of a two digit number is 3 more than the digit in the units place = 3 + b

So, the number = 10 (3 + b) + b

= 30 + 10b + b

= 30 + 11b