The digit in the tens place of a two digit number is three times that

1.	The digit in the tens place of a two digit number is three times that in the units place. If the digits are reversed, the new number will be 36 less than the original number. Find the original number.
Answer» Let the digits be x and y, so the number will be = (10x+y), on reversing the digits, the new number will be = (10y+x) According to the question we can write as x =3y and also we can write as 10y+x+36=10x+y Which implies 10y-y+36=10x-x 9y+36=9x Now substituting the value of x 9y+36=27y -18y=-36 y=2 and x=6 Now y=6+x=6+3=9 So the number is 62 To check: digit sum=6+2=8 Reversing the digit numbers becomes 26 and 26+36=62 Hence verified.

The digit in the tens place of a two digit number is three times that in the units place. If the digits are reversed, the new number will be 36 less than the original number. Find the original number.

Answer»

Let the digits be x and y, so the number will be = (10x+y), on reversing the digits, the new number will be = (10y+x)

According to the question we can write as x =3y and also we can write as 10y+x+36=10x+y

Which implies 10y-y+36=10x-x

9y+36=9x

Now substituting the value of x

9y+36=27y

-18y=-36

y=2 and x=6

Now y=6+x=6+3=9

So the number is 62

To check: digit sum=6+2=8

Reversing the digit numbers becomes 26 and 26+36=62

Hence verified.