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The digits of a positive number of three digits arein A.P and their sum is 15. The number obtainedby reversing the digits is 594 less than the originalnumber. Find the number O.D. Set II, 20161 3 |
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Answer» Let the number be (a-d), a, (a+d) (a+d)×100+a×10+(a−d)=111a+99d on reversing (a−d)×100+a×10+(a+d)⟹=111a−99da+d+a+a-d=15a=5 and d =3 |
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