The digits of a two-digit number differ by 3. If thedigits are interch

1.	The digits of a two-digit number differ by 3. If thedigits are interchanged, and the resulting number isadded to the original number we get 143. What canbe the original number?
Answer» Let us assume, the x is the tenth place digit and y is the unit place digit of the two-digit number. Also assume x > y Therefore, the two-digit number is 10x + y and reversed number is 10y + xGiven: x - y = 3 ---------------1 Also given: 10x + y + 10y + x = 14311x + 11y = 143x + y = 13 ---------------2 Adding equation 1 and equation 2 2x = 16x = 8 Therefore, y = x - 3 = 8 - 3 = 5 Therefore, the two-digit number = 10x + y = 10 * 8 + 5 = 85

The digits of a two-digit number differ by 3. If thedigits are interchanged, and the resulting number isadded to the original number we get 143. What canbe the original number?

Answer»

Let us assume, the x is the tenth place digit and y is the unit place digit of the two-digit number. Also assume x > y

Therefore, the two-digit number is 10x + y and reversed number is 10y + xGiven:

x - y = 3 ---------------1

Also given:

10x + y + 10y + x = 14311x + 11y = 143x + y = 13 ---------------2

Adding equation 1 and equation 2

2x = 16x = 8

Therefore, y = x - 3 = 8 - 3 = 5

Therefore, the two-digit number = 10x + y = 10 * 8 + 5 = 85