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The dimension of the quantity `vecExxvecB`, where `vecE` represents the electric field and `vecB` the magnetic field may be given asA. `MT^(-3)`B. `M^(2)LT^(-5)A^(-2)`C. `M^(2)LT^(-3)A^(-1)`D. `MLT^(-2)A^(-2)` |
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Answer» Electric field, `E=(F)/(q)=([MLT^(2)])/([AT][:T^(-1)])=[MLT^(-3)A^(-1)]` Magnetic field, `(F)/(q^(0))=([MLT^(-2)])/([AT][LT^(-1)])=[MT^(-2)A^(-1)]` `therefore` The dimensions of quantity `vecExxvecB=[MLT^(-3)A^(-1)]` `[MT^(-2)A^(-1)]=[M^(2)LT^(-5)A^(-2)]` |
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