1.

The dimensional formula for magnetic flux isA. `[ML^(2)T^(-2)A^(-1)]`B. `[ML^(3)T^(-2)A^(-2)]`C. `[M^(0)L^(-2)T^(2)A^(-2)]`D. `[ML^(2)T^(-1)A^(2)]`

Answer» Correct Answer - A
Mathematically, magnetic flux
`phi = B A` ...(i)
but magnetic force
`F = Bil` or `B = (F)/(il)`
Putting the value of B in Eq.(i), we have
`phi = (F)/(il)A`
Thus, dimensions of `phi = ([MLT^(-2)][L^(2)])/([AL])`
`= [ML^(2)T^(-2)A^(-1)]`


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