The dimensions for P = M L-1 T-1 Density = L-3 M surface tension = M T-2 Given T = P^a D^b S^c Powers of M = 0 Powers of L=0 Powers of T = 1 Powers of M = a+b+c =0 Powers of L = -a-3b = 0 3b = -a Powers of T = -a-2c = 1 Solving the three above equation we get a= -3/2 b= 1/2 c=1 In this how are the equations (in bold) solved. ? Let me know the steps involved while solving the 3 equations as I am not getting the required solution by solving the equations .

The dimensions for P = M L-1 T-1 Density = L-3 M surface tension = M

1.	The dimensions for P = M L-1 T-1 Density = L-3 M surface tension = M T-2 Given T = P^a D^b S^c Powers of M = 0 Powers of L=0 Powers of T = 1 Powers of M = a+b+c =0 Powers of L = -a-3b = 0 3b = -a Powers of T = -a-2c = 1 Solving the three above equation we get a= -3/2 b= 1/2 c=1 In this how are the equations (in bold) solved. ? Let me know the steps involved while solving the 3 equations as I am not getting the required solution by solving the equations .
Answer» The dimensions for P = M L-1 T-1 Density = L-3 M surface tension = M T-2 Given T = P^a D^b S^c Powers of M = 0 Powers of L=0 Powers of T = 1 Powers of M = a+b+c =0 Powers of L = -a-3b = 0 3b = -a Powers of T = -a-2c = 1 Solving the three above equation we get a= -3/2 b= 1/2 c=1 In this how are the equations (in bold) solved. ? Let me know the steps involved while solving the 3 equations as I am not getting the required solution by solving the equations .