1.

The dimensions of (a)/(b)in the equation P= (a^(2)-t^(2))/(bx)where P ispressure,x is distance and t is time are

Answer»

`[M^(2)LT^(-3)]`
`[ML^(0)T^(-2)]`
`[ML^(3)T^(-1)]`
`[M^(0)LT^(-3)]`

Solution :`pP= (a-t^(2))/(bx)` DIMENSIONS of `a= [T^(2)]` as `t^(2)` is subtracted from a.
From `P=(a-t^(2))/(bx)= (t^(2))/(bx)`
`:. [b]= ([t^(2)])/([Px])= ([T^(2)])/([ML^(-1)T^(-2)][L])= [M^(-1)L^(0)T^(4)]`
`:. [(a)/(b)]= ([T^(2)])/([M^(-1)L^(0)T^(4)])= [ML^(0)T^(-2)]`


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