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The dimensions of a rectangular block measured with callipers having least count of 0.01 cm are 5 mm xx 10 mm xx 5 mm. The maximum percentage error in the measurement of the volume of the block is |
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Answer» `5%` `V= Lxx B xx H` the maximum relative ERROR in V is `(DeltaV)/(V)= (DeltaL)/(L)+ (DeltaB)/(B)+(DeltaH)/(H)` THEMAXIMUM percentage error in V is `(DeltaV)/(V) xx 100= (DeltaL)/(L)xx 100+ (DeltaB)/(B)xx100+ (DeltaH)/(H)xx100` `= (0.01)/(0.5)xx 100+ (0.01)/(1.0)xx 100+ (0.01)/(0.5)xx 100= 2%+ 1%+ 2%= 5%` |
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