InterviewSolution
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The dimensions of a rectangular box are in the ratio of 2: 3: 4 and the difference between the cost of covering it with sheet of paper at the rates of Rs 8 and Rs 9.50 per m2 is Rs 1248. Find the dimensions of the box. |
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Answer» Given details are, Ratio of dimensions of rectangular box = 2:3:4 Let length of box be ‘2x’ m Let breadth of box be ‘3x’ m Let height of box be ‘4x’ m Area of sheet of paper required for covering it = total surface area of cuboid = 2 (lb+bh+hl) = 2 (2x×3x + 3x×4x + 4x×2x) = 2 (6x2 + 12x2 + 8x2) = 2 (26x2) = 52 x2 m2 Cost for covering with sheet of paper at the rate of Rs 9.50 /m2 = 52x2 × 9.50 = Rs 494x2 Cost for covering with sheet of paper at the rate of Rs 8 /m2 = 52x2 × 8 = Rs 416x2 Given, the difference between the cost of covering it with sheet of paper at the rates of Rs 8 and Rs 9.50 per m2 is Rs 1248 494x2 – 416x2 = 12448 78x2 = 1248 x2 = 1248/78 = 16 x = √16 = 4 ∴ Length of box = 2x = 2×4 = 8m Breadth of box = 3x = 3×4 = 12m Height of box = 4x = 4×4 = 16m |
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