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The dimensions of a room are (10 mx8mx 3.3 m). How many men can be accommodated in this room if each man requires 3 m3 of space? A. 99 B. 88 C. 77 D. 75 |
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Answer» We know that, Volume of a cuboid = Length × Breadth × Height Therefore, Volume of the room = 10 × 8 × 3.3 = 264 m3 Space required by 1 person = 3 m3 Therefore, Total number of people that can be accommodated = \(\frac{264}{3}\) = 88 Hence, option B is correct |
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